Saturday, December 7, 2013

22.3-22.4, due on December 9

Difficult:
    The instructions for calculating the Galois group of an arbitrary polynomial are absurd. You might as well crack RSA by factoring.

Reflective:
    I was most interested in the concept of the discriminant. Rather than doing a difficult process to find out exactly what the Galois group is, just rely a simple one to find out if it is in the alternating group or not.

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